The sum of three consecutive numbers is 84. What are the numbers?
You put it with regards to x and take away for each term.
x-1 + x-2 + x-3 =84.
Assemble like terms by moving every one of the numbers to the right hand side of the equivalents sign (not neglecting to rearrange their signs) and leaving every one of the x terms on the left.
x+x+x = 84 +1 +2 +3
Including three x terms is equivalent to increasing, so
3x = 90.
Right. To move that multiplier on the left, you move it to the right, again transforming the sign. The reversal of add is take away, and the reversal of duplicate is partition.
x=90/3 and 90/3 = 30 so x = 30.
Well bugger me, since what we began with was
x-1 + x-2 + x-3 =84 and presently we have an incentive for x we can simply connect it where x was.
30-1 + 30-2 + 30-3 =84.
29+28+27 = 84
29 + 28 is 57, and whacking 27 onto 57 is 84. Indeed, that evidently works, yet how about we do it with three additional numbers just to ensure.
10, 11, and 12 we'll pick as our back to back numbers so the inquiry presently could be three sequential numbers make 33, what are they?
Following similar advances:
x-1 + x-2 + x-3 =33.
x+x+x = 33 +1 +2 +3
3x = 39.
x= 39/3
x=13
13-1 + 13-2 + 13-3 =33.
12 +11+10 = 33